1.

A bag contains 1 red and 3 white balls. Find the probability distribution of the number of red balls if 2 balls are drawn at random from the bag one-byone without replacement.

Answer»

Let X be the random variable defined as the number of red balls.

Then X = 0, 1

P(X = 0) = \(\frac{3}{4}\times\frac{2}{3}=\frac{6}{12}=\frac{1}{2}\)

P(X = 1) = \(\frac{1}{4}\times\frac{3}{3}+\frac{3}{4}\times\frac{1}{3}=\frac{6}{12}=\frac{1}{2}\)

Probability Distribution Table:

X01
P(X)\(\frac{1}{2}\)\(\frac{1}{2}\)


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