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A bag contains 10 blue balls and 12 yellow balls. Another contains 15 blue balls and 7 yellow balls. a. What is the probability of getting a yellow ball from the first bag? b. What is the probability of getting a yellow ball from the second bag? C. If all the balls are put in a single bag, what is the probability of getting a yellow ball from it? |
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Answer» a. Total number of balls in the first bag = 10 + 12 =22, Number of yellow balls = 12 Probability of getting a yellow ball = \(\frac{12}{22}=\frac{6}{11}\) b. Total number of balls in the second bag = 15 + 7 = 22, Number of a yellow ball = 7 Probability of getting a yellow ball = \(\frac{7}{22}\) c. Total number of balls = 22 + 22 = 44 Number of yellow balls = 12 + 7 = 19 Probability of getting a yellow ball = \(\frac{19}{44}\) |
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