1.

A bag contains 10 blue balls and 12 yellow balls. Another contains 15 blue balls and 7 yellow balls. a. What is the probability of getting a yellow ball from the first bag? b. What is the probability of getting a yellow ball from the second bag? C. If all the balls are put in a single bag, what is the probability of getting a yellow ball from it?

Answer»

a. Total number of balls in the first bag = 10 + 12 =22, Number of yellow balls = 12

Probability of getting a yellow ball = \(\frac{12}{22}=\frac{6}{11}\)

b. Total number of balls in the second bag = 15 + 7 = 22, Number of a yellow ball = 7

Probability of getting a yellow ball = \(\frac{7}{22}\)

c. Total number of balls = 22 + 22 = 44 Number of yellow balls = 12 + 7 = 19

Probability of getting a yellow ball = \(\frac{19}{44}\)



Discussion

No Comment Found

Related InterviewSolutions