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A bag contains 50 p, 25 P and 10 p coins in the ratio 5: 9: 4, amounting to Rs. 206. Find the number of coins of each type. |
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Answer» Let the number of 50 p, 25 P and 10 p coins be 5x, 9x and 4x respectively. (5x/2)+( 9x/ 4)+(4x/10)=206 50x + 45x + 8x = 4120 103x = 4120 x=40. Number of 50 p coins = (5 x 40) = 200; Number of 25 p coins = (9 x 40) = 360; Number of 10 p coins = (4 x 40) = 160. |
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