1.

A bag contains 50 p, 25 P and 10 p coins in the ratio 5: 9: 4, amounting to Rs. 206. Find the number of coins of each type.

Answer»

Let the number of 50 p, 25 P and 10 p coins be 5x, 9x and 4x respectively. 

(5x/2)+( 9x/ 4)+(4x/10)=206

50x + 45x + 8x = 4120

103x = 4120 

x=40. 

Number of 50 p coins = (5 x 40) = 200; 

Number of 25 p coins = (9 x 40) = 360; 

Number of 10 p coins = (4 x 40) = 160.



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