1.

A bag contains 50 tickets numbered 1, 2, 3, ... 50 of which five are drawn at random and arranged in ascending order of magnitude (x_(1) < x(2) < x_(3) < x_(4) < x_(5)). The probability that x_(3) cdot x_(4) = 85 is

Answer»

`(.^(48)C_(3))/(.^(50)C_(5))`
`(99)/(.^(50)C_(5))`
`(99)/(5.^(49)C_(4))`
`(33)/(.^(49)C_(4))`

Solution :`{1,2,3,4} overset(5 17)(------){18,19,.....,50}`
Required probability = `(.^(4)C_(2) xx .^(33)C_(1))/(.^(50)C_(5)) = 99/(5.^(49)C_(4))`.


Discussion

No Comment Found

Related InterviewSolutions