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A bag contains 6 red balls, 8 green balls, and 8 white balls. One ball is drawn at random from the bag, find the probability of getting i. A white or green ball ii. Neither green ball nor a red ball. |
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Answer» Red balls = 6 Green balls = 8 White balls = 8 Total number of balls = 6 + 8 + 8 = 22 a. The probability of getting a white or green ball = 16/20 b. The probability of getting neither green balls nor a red ball = 8/20 |
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