InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
A bag contains 8 red, 6 white and 4 black balls. A ball is drawn at random from the bag. Find the probability that the drawn ball is (i) red or white (ii) not black (iii) neither white or black |
|
Answer» Total number of possible outcomes, n(S) = 18 (i) Number of favorable outcomes, n(E) = 14 ∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{14}{18}\) = \(\frac{7}{9}\) (ii) Number of events of getting a black ball, n(E) = 4 ∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{4}{18}\) = \(\frac{2}{9}\) Probability of not getting a black ball = 1 – P(E) = 1 - \(\frac{2}{9}\) = \(\frac{7}{9}\) (iii) Number of favorable outcomes, n(E) = 8 ∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{8}{18}\) = \(\frac{4}{9}\) |
|