A bag contains some number of white balls, twice the number of white b

1.	A bag contains some number of white balls, twice the number of white balls are blue balls, thrice the number of blue balls are the red balls. If the total number of balls in the bag are 27. Then calculate the number of balls of each colour present in the bag.
Answer» Let the number of white balls = x Number of blue balls = twice the number of white balls = 2(x) = 2x Number of red balls = thrice the number of blue balls = 3(2x) = 6x Total balls = White + Blue + Red = 27 ⇒ x + 2x + 6x = 27 ⇒ 9x = 27 ⇒ 9x/9 = 27/9 (Divide by 9 on both sides) ⇒ x = 3 Therefore white balls x = 3 Blue balls = 2x = 2(3) = 6 Red balls = 6x = 6(3) = 18

A bag contains some number of white balls, twice the number of white balls are blue balls, thrice the number of blue balls are the red balls. If the total number of balls in the bag are 27. Then calculate the number of balls of each colour present in the bag.

Answer»

Let the number of white balls = x

Number of blue balls = twice the number of white balls = 2(x) = 2x

Number of red balls = thrice the number of blue balls = 3(2x) = 6x

Total balls = White + Blue + Red = 27

⇒ x + 2x + 6x = 27 ⇒ 9x = 27

⇒ 9x/9 = 27/9 (Divide by 9 on both sides)

⇒ x = 3

Therefore white balls x = 3

Blue balls = 2x = 2(3) = 6

Red balls = 6x = 6(3) = 18