A bag contains three green marbles, four blue marbles, and two orange

1.	A bag contains three green marbles, four blue marbles, and two orange marbles. If a marble is picked at random, then the probability that it is not an orange marble isA \(\frac{1}4\)B \(\frac{1}3\)C \(\frac{4}9\)D \(\frac{7}9\)
Answer» Total numbers of elementary events are: 3+ 4 + 2= 9 Let E be the event of getting not an orange marble Numbers of Favorable outcomes are: 3 + 4 = 7 P (not an orange marble) = P (E) = \(\frac{7}9\)

A bag contains three green marbles, four blue marbles, and two orange marbles. If a marble is picked at random, then the probability that it is not an orange marble isA \(\frac{1}4\)B \(\frac{1}3\)C \(\frac{4}9\)D \(\frac{7}9\)

Answer»

Total numbers of elementary events are: 3+ 4 + 2= 9

Let E be the event of getting not an orange marble

Numbers of Favorable outcomes are: 3 + 4 = 7

P (not an orange marble) = P (E) = \(\frac{7}9\)

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A bag contains three green marbles, four blue marbles, and two orange marbles. If a marble is picked at random, then the probability that it is not an orange marble isA \(\frac{1}4\)B \(\frac{1}3\)C \(\frac{4}9\)D \(\frac{7}9\)

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