InterviewSolution
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InterviewSolution
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A bag of mass `M` hangs by a long massless rope. A bullet of mass in, moving horizontally with velocity `u`, is caught in the bag. Then for the combined (bag `+` bullet) system, just after collisionA. momentum is `"mu"M//(M+m)`B. kinetic energy is `"mu"^2//2`C. momentum is `"mu"(M+m)//M`D. kinetic energy is `m^(2)u^(2)//2(M+m)` |
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Answer» Correct Answer - D Let combined velocilty of the system be `v` `(m+MV)v="mu"impliesv=("mu")/(m+M)` `KE=1/2(m+M)v^(2)=(m^(2)u^(2))/(2(M+m))` |
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