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A ball dropped from a height of 2 m rebounds to a height of 1.5 m after hitting the ground. Then the percentage of energy lost is |
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Answer» 25% % ENERGY LOST = `(U_1 - U_2)/(U_1) xx 100% = (mgh_1 - mgh_2)/(mgh_1) xx 100%` `= ((h_1 - h_2)/(h_1)) xx 100% = (2 - 1.5)/(2) xx 100% = 25%`. |
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