1.

A ball dropped from a height of 2 m rebounds to a height of 1.5 m after hitting the ground. Then the percentage of energy lost is

Answer»

25
30% 
50% 
100% 

Solution :`U_1 = mgh_1 and U_2 = mgh_2`
% ENERGY LOST = `(U_1 - U_2)/(U_1) xx 100% = (mgh_1 - mgh_2)/(mgh_1) xx 100%`
`= ((h_1 - h_2)/(h_1)) xx 100% = (2 - 1.5)/(2) xx 100% = 25%`.


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