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A ball dropped from the top of a tower covers a distance `7x` in the last second of its journey, where `x` is the distance covered in the first second. How much time does it take to reach to ground?.A. 3 sB. 4 sC. 5 sD. 6 s |
Answer» Correct Answer - B In first second distance travelled, `x=(1)/(2)xx g xx t^(2)=5m` (for `g=10 ms^(-2))` in last second `7x=35 m` Now, `S_(t)th=(u+at-(1)/(2)a)` `rArr 35=0+10xx t-(1)/(2)xx10` `therefore t=4s` |
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