A ball falling with velocity vec(v_(i))=(-0.65hati-0.35hatj)ms^(-1) is subjected toa net impulse vecI=(0.6hati+0.18 hatj)Ns. If the ball has a mass of 0.275 kg, calculate its velocity immediately following the impulse.

A ball falling with velocity vec(v_(i))=(-0.65hati-0.35hatj)ms^(-1) is

1.	A ball falling with velocity vec(v_(i))=(-0.65hati-0.35hatj)ms^(-1) is subjected toa net impulse vecI=(0.6hati+0.18 hatj)Ns. If the ball has a mass of 0.275 kg, calculate its velocity immediately following the impulse.
Answer» Solution :`MVEC(v_(f))-mvec(v_(i))=VECI, VEC(v_(f))=vec(v_(i))+(vecI)/(m)` `vec(v_(f))=-0.65hati-0.35hatj+(0.6hati+0.18hatj)/(0.275)` `vec(v_(f))=-0.65hati-0.35hatj+2.18hati+0.655hatj` `vec(v_(f))=(1.53hati+0.305hatj)ms^(-1)`