A ball is a thrown from the top of a tower of 61 mhigh with a velocity 24.4 ms^(-1) at an elevation of 30^(@) above the horizontal. What is the distance from the foot of the tower to the point where the ball hits the ground ?

A ball is a thrown from the top of a tower of 61 mhigh with a velocity

1.	A ball is a thrown from the top of a tower of 61 mhigh with a velocity 24.4 ms^(-1) at an elevation of 30^(@) above the horizontal. What is the distance from the foot of the tower to the point where the ball hits the ground ?
Answer» Solution : `h = (1)/(2)g t^(2) - (u SIN THETA)t rArr t = 5 "seconds"` ALSO, `d = (u COS theta)t = 105.65 m`