A ball is dropped from the top of a building. It takes 0.5s to fall past the 3m length of a window some distance from the top of the building. If the velocity of the ball at the top and the bottom of the window are V_(T) and V_(8) respectively then V_(T)+V_(B)=?

A ball is dropped from the top of a building. It takes 0.5s to fall pa

1.	A ball is dropped from the top of a building. It takes 0.5s to fall past the 3m length of a window some distance from the top of the building. If the velocity of the ball at the top and the bottom of the window are V_(T) and V_(8) respectively then V_(T)+V_(B)=?
Answer» SOLUTION :`S=((u+V)/(2))t` `3=(v_(T)+v_(B)/(2))0.5` `V_(T)+V_(b)=12m//s`