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A ball is dropped into a well in which the water level is at a depth `h` below the top. If the speed of sound id `C`, then the time after which the splash is heard will be give by.A. `h[sqrt((2)/(gh))+(1)/(c)]`B. `h[sqrt((2)/(gh))+(1)/(c)]`C. `h[(2)/(g)+(1)/(c)]`D. `h[(2)/(g)+(1)/(c)]` |
Answer» Correct Answer - A Time of fall `=sqrt((2h)/(g))` Time taken by the sound to come out =`(h)/(c)` `Total time `=sqrt((2h)/(g)) +(h)/(c) =h [ sqrt((2)/(gh)) +(1)/(2)]`. |
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