A ball is hanging vertically by a light inextensible string of length L from fixed point O. The ball of mass m is given a speed u at the lowest position such that it completes a vertical circle with centre at O as shown. Let AB be a diameter of circular path of ball making an angle theta with vertical as shown. (g is acceleration due to gravity) a) Let T_A and T_B be tension in string when ball is at A and B respectively, then find T_A – T_B.(b) Let vec(a)_(A) and vec(a)_(B) be acceleration of ball when it is at A and B respectively, then find the value of |vec(a)_(A)+vec(a)_(B)|

A ball is hanging vertically by a light inextensible string of length

1.	A ball is hanging vertically by a light inextensible string of length L from fixed point O. The ball of mass m is given a speed u at the lowest position such that it completes a vertical circle with centre at O as shown. Let AB be a diameter of circular path of ball making an angle theta with vertical as shown. (g is acceleration due to gravity) a) Let T_A and T_B be tension in string when ball is at A and B respectively, then find T_A – T_B.(b) Let vec(a)_(A) and vec(a)_(B) be acceleration of ball when it is at A and B respectively, then find the value of \|vec(a)_(A)+vec(a)_(B)\|
Answer» ANSWER :`(a) 6mg COS THETA ` `(B) gsqrt(4+12 cos^(2) theta)`