A ball is projected from a certain point on the ground at an angle with the horizontal surface. The horizontal and vertical displacement x and y(in metres) vary with time (in seconds) asx=10√3ty=10t−5t2What is the magnitude and direction of the velocity of projection?

A ball is projected from a certain point on the ground at an angle wit

1.	A ball is projected from a certain point on the ground at an angle with the horizontal surface. The horizontal and vertical displacement x and y(in metres) vary with time (in seconds) asx=10√3ty=10t−5t2What is the magnitude and direction of the velocity of projection?
Answer» A ball is projected from a certain point on the ground at an angle with the horizontal surface. The horizontal and vertical displacement x and y(in metres) vary with time (in seconds) as $x = 10 \sqrt{3} t$ $y = 10 t - 5 t^{2}$ What is the magnitude and direction of the velocity of projection?

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A ball is projected from a certain point on the ground at an angle with the horizontal surface. The horizontal and vertical displacement x and y(in metres) vary with time (in seconds) asx=10√3ty=10t−5t2What is the magnitude and direction of the velocity of projection?

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