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A ball is projected from a cliff of height h = 19.2 m at an angle a to the horizontal. It hits an incline passing through the foot of the cliff, inclined at an angle theta to the horizontal. Time of flight of the ball is T = 2.4 s. Foot of the cliff is the origin of the co-ordinate system, horizontal is x direction and vertical is y direction (see figure). Plot of y co-ordinate vs time and y component of velocity of the ball (v_(y)) vs its x co-ordinate (x) is as shown.x and y are in m and time is in s in the graph. [g = 10 m//s^(2)] (a) Find the angle of projection a (b) Find the inclination (theta) of the incline. (c) If the ball is projected with same speed but at an angle theta (= inclination of incline) to the horizontal, will it hit the incline above or below the point where it struck the incline earlier?

Answer» <html><body><p><br/></p>Answer :(a) `<a href="https://interviewquestions.tuteehub.com/tag/alpha-858274" style="font-weight:bold;" target="_blank" title="Click to know more about ALPHA">ALPHA</a> = <a href="https://interviewquestions.tuteehub.com/tag/tan-1238781" style="font-weight:bold;" target="_blank" title="Click to know more about TAN">TAN</a>^(-) ((3)/(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>))` (b) `theta = tan^(-) (1)/(2)` (c) The ball will <a href="https://interviewquestions.tuteehub.com/tag/hit-1028201" style="font-weight:bold;" target="_blank" title="Click to know more about HIT">HIT</a> at a point lower than the earlier <a href="https://interviewquestions.tuteehub.com/tag/spot-1222851" style="font-weight:bold;" target="_blank" title="Click to know more about SPOT">SPOT</a>.</body></html>


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