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A ball is projected from ground in such a way that after 10 seconds of projection it lands on ground 500 m away from the point of projection. Find out :- (i) angle of projection (ii) velocity of projection (iii) Velocity of ball after 5 seconds |
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Answer» Correct Answer - (i)`theta=45^(@)` (ii)`50sqrt(2)m//s` (iii)`50m//sec` |
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