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A ball is projected from the ground with velocity `u` such that its range is maximum ThenA. Its velocity at half the maximum height is `sqrt3/2u`B. Its velocity at the maximum height is `u`C. Change in its velocity when it returns to the ground is `u`D. all the above are true |
Answer» Correct Answer - A At half of max height velocity `(V)=usqrt((1+cos^(2)theta)/(2))` |
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