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A ball is projected horizontal from the top of a tower with a velocity `v_(0)`. It will be moving at an angle of `60^(@)` with the horizontal after time.A. `(v_(0))/(sqrt(3)g)`B. `(sqrt(3)v_(0))/(g)`C. `(v_(0))/(g)`D. `(v_(0))/(g)` |
Answer» Correct Answer - B `tan 60^(@) = (v_(V))/(v_(H)) = (g t)/(v_(0))` `:. T = (sqrt(3)v_(0))/(g)` |
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