1.

A ball is projected with velocity v_(0) = sqrt(gh) at an angle 'theta' to the horizontal towards a vertical smooth wall distant 'd' from the point of projection. After collision the ball returns to the point of projection. The coefficient of restitution is

Answer»

`(d)/(h sin THETA - d)`
`(d)/(2h sin theta-d)`
`(d)/(h sin 2 theta-d)`
`(d)/(sin 2theta + 2D)`

Answer :C


Discussion

No Comment Found