1.

A ball is released from a height .h. above the ground. It makes several collisions with the ground. What is the time interval between the instants it was released and it makes 2nd impact with the ground in terms of co-efficient of restitution .e. between ground and ball ?

Answer»

SOLUTION :`T =t _(1) + 2 t _(2) = sqrt ((2h)/( g )) +2 sqrt ((2h _(1))/( g )) +2 sqrt (( 2)/(g) (E ^(2) H )) implies T = sqrt ((2h)/( g )) (1 + 2e) `


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