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A ball is released from the top at a tower of height h meters. It takes T seconds to reach the ground. What is the position of the ball at T1/3 second. (1) 17h/18 meters from the ground(2) 17h/9 meters from the ground (3) 8h/9 meters from the ground (4) h/9 meters from the ground |
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Answer» Answer is (3) 8h/9 meters from the ground h = (1/2) gT2. and h’ = (1/2) g(T/2)2 h/h’ = 9 or h’ = h/9 Distance from ground = h - h’ = h - (h/9) = 8h/9 |
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