InterviewSolution
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InterviewSolution
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A ball is released from the top of a tower of height 8h metre. It takes T second to reach the ground. What is the position of the ball in T/3 second?R |
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Answer» the ACCELERATION of the ball will be g. Initial VELOCITY will be 0. in T sec. body travels h mts. by applying equations of motion we gets=ut+(1/2)GT 2 h=(1/2)gT 2 ------[1]in T/3 sec h 1 =(1/2)gT 2 =(1/2)g( 3T ) 2 =(1/2)g( 9T 2 ) -------[2]from [1] and [2] we get h 1 = 9h distance from point of release.therefore distance from GROUND is h− 9h = 98h EXPLANATION:Please Mark me as brainliest :) |
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