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A ball is released from the top of a tower of height h metre. It takes T second to reach the ground. What is the position of the ball in `T/3` second?A. `h/9`metre from the groundB. `(7h//9)` metre from the groundC. `(8h//9)` metre from the groundD. `(17h//18)` metre from the ground |
Answer» Correct Answer - C `h=1/2 gT^2` At `T/3` second, distance fallen `d=1/2 g(T/3)=h/9` `:.` Height from ground =`h-d=(8h)/9` |
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