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A ball is released from the top of a tower of height h metre. It takes T second to reach the ground. What is the position of the ball in `T/3` second?A. ` h//9 m`B. ` 7h//9 m`C. ` 8h//9m`D. ` 17 h//18 m` |
Answer» Correct Answer - C We have `h=(1)/(2)g T^(2)` In `T//3` second, distance fallen `=(1)/(2) g((T)/(3))^(2) =(h)/(9)` So position of the ball from the ground is `h-(h)/(9)=(8h)/(9)m`. |
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