A ball is thrawn downward from a height of 30m with a velocity of 10 ms^(-1).Determine the velocity with which the ball strikes the ground by using law of conservation of energy.

A ball is thrawn downward from a height of 30m with a velocity of 10 m

1.	A ball is thrawn downward from a height of 30m with a velocity of 10 ms^(-1).Determine the velocity with which the ball strikes the ground by using law of conservation of energy.
Answer» <html><body><p></p>Solution :Height from which the ball is <a href="https://interviewquestions.tuteehub.com/tag/dropped-2594665" style="font-weight:bold;" target="_blank" title="Click to know more about DROPPED">DROPPED</a> = 30 m <br/>Velocity with which the ball is dropped=`10 <a href="https://interviewquestions.tuteehub.com/tag/ms-549331" style="font-weight:bold;" target="_blank" title="Click to know more about MS">MS</a>^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)` <br/>According to law of conservation of energy, <br/>Gain in kinetic energy=Loss in <a href="https://interviewquestions.tuteehub.com/tag/potential-1161228" style="font-weight:bold;" target="_blank" title="Click to know more about POTENTIAL">POTENTIAL</a> energy<br/>For bodies falling down `v62 = u^2 + 2gh ` <br/>` v^2 = (10)^2 + 2 xx 9.8 xx 30 = 688` <br/> ` v = 26.23 ms^(-1)`</body></html>