A ball is thrawn downward from a height of 30m with a velocity of 10 ms^(-1).Determine the velocity with which the ball strikes the ground by using law of conservation of energy.

A ball is thrawn downward from a height of 30m with a velocity of 10 m

1.	A ball is thrawn downward from a height of 30m with a velocity of 10 ms^(-1).Determine the velocity with which the ball strikes the ground by using law of conservation of energy.
Answer» Solution :Height from which the ball is DROPPED = 30 m Velocity with which the ball is dropped=`10 MS^(-1)` According to law of conservation of energy, Gain in kinetic energy=Loss in POTENTIAL energy For bodies falling down `v62 = u^2 + 2gh ` ` v^2 = (10)^2 + 2 xx 9.8 xx 30 = 688` ` v = 26.23 ms^(-1)`