1.

A ball is thrown from the ground into air. AT a height of ` 9.0 m`, the velcoity is obsecred ot be ` vec v = 7.0 hat i+ 6.0 hat j`. Find the masimum hight to which the ball will rise. ` g= 10 ,s^(-2)`.

Answer» Here, ` v_x = 7 ms^(-1)` , v_y =6.0 ms^(-1) , S= 9.0 m,
` u_y = ?`
Taking vertical upward motion of the ball up to given height, we have
` v_y^2 = u_y^2 + 2 a S`
` 6^2 = u_y^2 +2 (- 10) xx 9`
or ` u_y^@ = 36 + 180 = 216`
Maximum height attanied by the ball,
` h_(max). = u_y^2/(2 g) = ( 216)/(2 xx 10) = 10.8 m`.


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