1.

A ball is thrown up and attains a maximum height of 100 m, it is thrown upwards with a speed of:A. 9.8 ms-1B. 44.2 ms-1C. 19.69 ms-1D. 98 ms-1

Answer»

A ball is thrown upward. So,

Initial Speed = u

Distance = s = 100 m

Final Speed = v = 0

Acceleration = a = g = -9.8 ms-2 (negative, since acceleration is opposite the motion)

Now,

v2 = u2 + 2as

0 = u2 - 2 x 9.8  x 100

u = \(\sqrt {2\times9.8\times100}\)

u = 44.27 ms-1

Hence, option B is correct.



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