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A star 2.5 times the mass of the Sun and collapsed to a size of 12 km rotates with a speed of 1.2 rev. per second. (Extremely compact stars of this kind are known as neutrons stars. Certain observed stellar objects called pulsars are believed to belong to this category). Will an object placed on its equator emain stuck to its surface due to gravity? (mass of the Sun 2 x 1030 kg) |
Answer» Acceleration due to gravity, g = GM/R2 = {(6.67 x 10-11) x (5 x 1030)/(12 x 103)2}m = 2.316 x 1012 ms-2 Centrifugal acceleration, = Rω2 = (12 x 103) x (3π)2 = 1.066 x 106 ms-2 As g > rω2, the body will remains stuck with the surface of the star |
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