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A ball is thrown vertically upwards from a height of 40 m and hits the ground with a speed that is three times its initial seepd. What is the time taken (in sec) for the fall ? |
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Answer» Correct Answer - 4 `9v^(2)=v^(2)+2xx10x40` `v^(2)=100, u=10 m//s` `s/t=(v+u)/2` `rArr (-40)/t= (10-30)/2=-10` `t=4 sec` |
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