1.

A ball is thrwon from the top of a tower of 61 m high with a velocity 24.4ms^(-1) at an elevation of 30^(@) above, the horizontal. What is the distance from the foot of the tower to the point where the ball hits the ground ?

Answer»

SOLUTION :
`h=(1)/(2)"gt"^(2)-(usintheta)t RARR t=5` SECONDS
Also, `d=(ucostheta)t = 105.65m`


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