A ball is thrwon from the top of a tower of 61 m high with a velocity 24.4ms^(-1) at an elevation of 30^(@) above, the horizontal. What is the distance from the foot of the tower to the point where the ball hits the ground ?

A ball is thrwon from the top of a tower of 61 m high with a velocity

1.	A ball is thrwon from the top of a tower of 61 m high with a velocity 24.4ms^(-1) at an elevation of 30^(@) above, the horizontal. What is the distance from the foot of the tower to the point where the ball hits the ground ?
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_DOC_OBJ_PHY_XI_V01_A_C04_SLV_045_S01.png" width="80%"/> <br/> `h=(1)/(2)"gt"^(2)-(usintheta)t <a href="https://interviewquestions.tuteehub.com/tag/rarr-1175461" style="font-weight:bold;" target="_blank" title="Click to know more about RARR">RARR</a> t=5` <a href="https://interviewquestions.tuteehub.com/tag/seconds-1198593" style="font-weight:bold;" target="_blank" title="Click to know more about SECONDS">SECONDS</a> <br/> Also, `d=(ucostheta)t = 105.65m`</body></html>