InterviewSolution
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InterviewSolution
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A ball moving with velocity `2 ms^(-1)` collides head on with another stationary ball of double the mass. If the coefficient of restitution is `0.5`, then their velocities (in `ms^(-1)`) after collision will beA. `0,2`B. `0,1`C. `1,1`D. `1,0.5` |
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Answer» Correct Answer - B Here, `u_(1)=2 m//s, u_(2)=0, e=0.5,` `m_(1)=m, m_(2)=2m` As momentum is conserved `:. m_(1)u_(1)+m_(2)u_(2)=m_(1)upsilon_(1)+m_(2)upsilon_(2)` ` mxx2+2 mxx0=m upsilon_(1)+2 m upsilon_(2)` or `upsilon_(1)+2 upsilon_(2)=2 ....(1) ` As coefficient of restitution `e=(upsilon_(2)-upsilon_(1))/(u_(1)-u_(2))` `0.5=(upsilon_(2)-upsilon_(1))/(2-0)` or `upsilon_(2)-upsilon_(1) ......(ii)` Adding `(i)` and `(ii)` `3 upsilon_(2)=3` or `upsilon_(2)=1 m//s` `upsilon_(1)=0 m//s` |
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