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A perosn is holding a bucket by applying a force of 20N. He moves a horizontal distance of 15m first and then climbs up a distance of 12m. What is the total work done by him? |
Answer» Here, `F=20N, s_(1)=15m, theta_(1)=90^(@)` `s_(2)=12m, theta_(2)=0^(@), W=?` `W=W_(1)+W_(2)=Fs_(1)costheta_(1)+Fs_(2)costheta_(2)` `=20xx15cos90^(@)+20xx12cos0^(@)` `W=0+240=240J` |
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