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A ball moving with velocity 2m/s collides head on with another stationaryball of double the mass . If coefficient of restitution is 0.5 then their velocities after collision will be ………. ms^(-1) . |
Answer» <html><body><p>0,1<br/>1,1<br/>`1,0.05`<br/>0,2</p>Solution :Coefficient of restitution ` e = (v_(1)^(.)-v_(2)^(.))/(v_(2)-v_(1))` <br/> ` :. 0.5 = (v_(2)-v_(1))/2 ` <br/> ` :. V_(2) = 1 + v_(1) ""………(1)` <br/> From conservation of momentum <br/> `mv_(1)+2mv_(2)=mv_(1)+2mv_(2),v_(1)=2m//s <a href="https://interviewquestions.tuteehub.com/tag/nd-576191" style="font-weight:bold;" target="_blank" title="Click to know more about ND">ND</a> v_(2) = 0 ` <br/> ` 2m = mv_(1) +2mv_(2) "".....(2)` <br/> From <a href="https://interviewquestions.tuteehub.com/tag/equation-974081" style="font-weight:bold;" target="_blank" title="Click to know more about EQUATION">EQUATION</a> (1) and (2) <br/> ` :. 2 = v_(1)+2(1+v_(1))` <br/> ` :. 2 =v_(1)+2+2v_(1)` <br/> ` :. 3v_(1)=0` <br/> ` :. v_(1)=0`<br/> From equation (1) `v_(2) =1 ` m/s .</body></html> | |