A ball of 200 g is at one end of a string of length 20 cm. It is revolved in a horizontal circle at an angular frequency of 6 rpm. Find (i) the angular velocity, (ii) the linear velocity, (iii) the centripetal acceleration,

A ball of 200 g is at one end of a string of length 20 cm. It is revol

1.	A ball of 200 g is at one end of a string of length 20 cm. It is revolved in a horizontal circle at an angular frequency of 6 rpm. Find (i) the angular velocity, (ii) the linear velocity, (iii) the centripetal acceleration,
Answer» SOLUTION :(i) The angular VELOCITY, `omega = (2pi N)/(t) = (2pi xx 6)/(60) = (pi)/(5) = 0.6284 "rad s"^(-1)` (ii) The LINEAR velocity, `v = r omega` `= 0.20 xx 0.6284 = 0.1257 ms^(-1)` (iii) The CENTRIPETAL acceleration, `a_(c) = r omega^(2)` `= 0.20 xx (0.6284)^(2) = 0.0790 ms^(-2)`.