A ball of 200g is at one end of a string of length 20cm. It is revolved ina horizontal circle at an angular frequency of 6 rpm. Find (i) the angular velocity, (ii) the linear velocity, (iii) the centripetal acceleration,

A ball of 200g is at one end of a string of length 20cm. It is revolve

1.	A ball of 200g is at one end of a string of length 20cm. It is revolved ina horizontal circle at an angular frequency of 6 rpm. Find (i) the angular velocity, (ii) the linear velocity, (iii) the centripetal acceleration,
Answer» Solution :(i) The angular velocity , `OMEGA = (2piN)/(t) = (2pixx6)/(60) = (pi)/(5) = 0.6284 rad s^(-1)`. (ii) Thelinear velocity, `v = romega` `=0.20xx0.6284 = 0.1257m s^(-1)` (iii) The centripetal acceleration, `a_( C) = R omega^(2)` `=0.20xx(0.6284)^(2)=0.0790m s^(-2)`.