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A ball of mas m moving t a speed v makes a head on collisiobn with a identicalbl at rest. The kinetic energy of the blls after the collision is three fourths of the original. Find the coefficient of retitutioin. |
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Answer» Mas of 1st ball =m and speed =v Mass of 2nd ball =m Let fiN/Al velocities of 1st and 2nd ball are `v_1 and v_2` respectively Using law of conservation of momentum `m(v_1+v_2)=mv`……i `rarr v_1+v_2=v`…………ii `also v_1-v_2=ev` Given that fiN/Al K.E.`=3/4 initial K.E. `rarr 1/2 mv_1^2+1/2mv_2^2=3/4xx1/2mv^2` `rarr v_1^2+v_2^2=3/4v^2` `rarr v_1^2+v_2^2=3/4v^2` `rarr ((v_1+v_2)^2+(v_1-v_2)^2)/2=3/4v^2` `rarr ((1+e^2)v^2)/2=3/4v^2` rarr 1+e^2=(3/2)` `rarr e^2=1/2` `-e=1/sqrt2` |
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