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A ball of mass 0.20 kg hits a wall at an angle of 45^(@) with a velocity of 25 m/sif the ball reboundat 90^(@)to the direction of incidence calculate the change in momentum of the ball. |
Answer» Solution : CHANGE is momentum`= (-mv COS 45^(@))` `-(mv cos 45^(@))` dp= 2mv `cos 45^(@) ` `|vec(dp)| = 2xx 0.2xx 25 xx (1)/(SQRT(2))` `:.Dp = 5 sqrt(2) Ns` |
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