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A ball of mass 1 kg carrying a charge `10^(-8)C` moves from a point A at potential 600 V to a point B at zero potential. The change in its kinetic energy isA. `-6xx10^(-6)"erg"`B. `-6xx10^(-6)J`C. `6xx10^(-6)J`D. `6xx10^(-6)"erg"` |
Answer» Correct Answer - C As work is done by the fiel, KE of the body increased `therefore" "DeltaKE=W=q(V_(A)-V_(B))` `=10^(-8)(600-0)=6xx10^(-6)J` |
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