A ball of mass m is dropped from a heighth on a platform fixed at the top of a vertical spring, as shown in figure. The platform is depressed by a distance x. Then the spring constant is

A ball of mass m is dropped from a heighth on a platform fixed at the

1.	A ball of mass m is dropped from a heighth on a platform fixed at the top of a vertical spring, as shown in figure. The platform is depressed by a distance x. Then the spring constant is
Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/mg-1095425" style="font-weight:bold;" target="_blank" title="Click to know more about MG">MG</a>)/((h + x))`<br/>`(mg)/((h + 2x))`<br/>`(2mg(h + x))/(x^2)`<br/>`(mg)/((2h + x)`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Loss in potential energy of the <a href="https://interviewquestions.tuteehub.com/tag/ball-891849" style="font-weight:bold;" target="_blank" title="Click to know more about BALL">BALL</a> = `mg(h + x)` <br/> Gain in elastic potential energy of the spring = `1/2 kx^2` <br/> According to the <a href="https://interviewquestions.tuteehub.com/tag/law-184" style="font-weight:bold;" target="_blank" title="Click to know more about LAW">LAW</a> of conservation of mechanical energy <br/> `mg(h + x) = 1/2 kx^2 " or " k = (2mg (h + x))/(x^2)` .</body></html>