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A ball of mass m is projected from the ground with an initial velocity u making an angle of `theta` with the vertical. What is the change in velocity between the point of projection and the highest point ?A. `u cos theta` downwardB. `u cos theta` upwardC. `u sin theta` upwardD. `u sin theta` downward |
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Answer» Correct Answer - A `Deltav = aDeltat = a ((T)/(2)) = (-g hatj) ((u cos theta)/(g)) = (-u cos theta) hatj` Therefore, change in velocity is `u cos theta` in downward direction. |
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