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A ball of mass 'm' kg hangs from a spring of constant 'k'. The ball oscillates with a period of 'T' seconds. If the ball is removed the spring is shortened by |
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Answer» SOLUTION :`T= 2pisqrt((m)/(k))` we get `(1)/(k)= (T^(2))/((2pi)^(2)m) implies k= (4pi^(2))/(T^(2))m` …….(1) For equilibrium `KX= MG implies X= (mg)/(k)`…….(2) substitute (1) and (2) `implies x= (gT^(2))/(4pi^(2))` |
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