A ball of mass m kg hangs from a spring of constant k. The ball oscillates with a period of T seconds. If the ball is removed the spring is shortened by

A ball of mass m kg hangs from a spring of constant k. The ball oscill

1.	A ball of mass m kg hangs from a spring of constant k. The ball oscillates with a period of T seconds. If the ball is removed the spring is shortened by
Answer» Solution :Using `T=2pisqrt(m/K)`, we GET `1/k` `=(T^(2))/((2pi)^(2)m)impliesk=((4pi)^(2))/(T^(2))m`…………1 For equilibrium `kx=mgimpliesx=(MG)/k` ……….2 Substitute 1 in 2 `impliesx=(gT^(2))/(4pi^(2))`