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A ball of mass mis released from the top of an inclined plane of inclination `theta` as shown. It strikes a rigid surface at at a distance `(3l)/(4)` from top elastically. Impulse imparted to ball by the rigid surface is A. `msqrt(3/2)gh`B. `msqrt(3gh)`C. `2msqrt(3gh)`D. `msqrt(6gh)` |
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Answer» Correct Answer - D Loss in PE = gain in KE `mgh_(1) = 1/2mv^(2)` `mg xx 3/4h = 1/2mv^(2) rArr v=sqrt(3gh)/2` Now, impulse imparted, `J = 2mv = 2msqrt(3gh)/2` = `msqrt(6gh)` |
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