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A ball of mass of 150g and velocity 12 ms^(-1) coming towards a batsman is hit by him with a force in such a way that the ball moves with velocity 30 ms^(-1) in the direction opposite to its original one. The time of contact between the ball and the bat is 0.01 s. Then the force applied on it by the batsman i s ....... |
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Answer» Solution :`Delta VEC( p ) = mv_(2)- vec( mv )_(2)` `=m(v_(2) - v_(1))` `=0.15 |30hat(I ) - (-12 hat(j ))` `=0.15[42hat(j )]` `vec( F )= (Delta vec(p ))/(Delta t )` `=(6.3)/( 0 .01)` `|vec(F ) | =630 N` |
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