1.

A ball of relative density 0.8 falls into water from a height of 2m. Find the depth to which the ball will sink (neglect viscous forces)

Answer»

Solution :Retardation of the ball INSIDE the water
`a=("upthrust - weight")/("mass")=("V(1)g - V(0.8)g")/("V(0.8)"),a=(g)/(4)`
Now, `v_(2)^(2)=v_(1)^(2)-2ah^(1)[v_(1)=SQRT(2gh)&v_(2)=0]`
Substituting the values, we get `h=8m`


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