Saved Bookmarks
| 1. |
A ball of relative density 0.8 falls into water from a height of 2m. Find the depth to which the ball will sink (neglect viscous forces) |
|
Answer» Solution :Retardation of the ball INSIDE the water `a=("upthrust - weight")/("mass")=("V(1)g - V(0.8)g")/("V(0.8)"),a=(g)/(4)` Now, `v_(2)^(2)=v_(1)^(2)-2ah^(1)[v_(1)=SQRT(2gh)&v_(2)=0]` Substituting the values, we get `h=8m` |
|