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A ball projected with a velocity of `10m//s` at angle of `30^(@)` with horizontal just clears two vertical poles each of height `1m`. Find separation between the poles. |
Answer» `h=u_(y)t+1/2g t^(2)=(10sin 30^(@))t+1/2(-10)t^(2)` `1=5t-5t^(2) rArr t=0.72s,2.76s` are the instants at which projectile crosses the poles `:.` Separation between poles `=OS-OQ` `=u cos theta (t_(2)-t_(1))` `=10cos 30^(@)(2.72-0.72)=17.7m` |
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