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A ball reaches a racket at `60m//s` along +X dirction and leaves the racket in the opposite direaction with the same speed. Assuming that the mass of the ball as `50gm` and the contact time is `0.02` second the force exerted by the racket on the ball is .A. `300N` along `+X` directionB. `300N` along `-X` directionC. `3,00,000 N` along `+X` directionD. `3,00,000 N` along `-X` direction |
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Answer» Correct Answer - B `F_(avg) =ma,a = (v-u)/(t)` |
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